Problem 1: Fruit Ninja

• Take all the favorite 6-letter words from your group and concatenate them into a single string (you can choose the order)
• Your goal is to then create as many fruit strings as possible, using only concatenation, selection, and slicing.
• One point for each selection statement, 2 points for each slice of at least 2 characters!
• Example:
  • If my single string was: s = "DANGERBOTTLECHANCEBRIGHT"
  • I could get "BANANA" with s[6] + s[1:3] + s[-10:-8] + s[1] for 6 points
• How many points can your group get in the time allotted? What is your highest scoring fruit?

Problem 2: Clean Up Time

• Consider the starting string

  s = " --- ERROR_USER: jAnE.dOe@mAiL_sErVeR.CoM !!! "

• Your task is to systematically clean up and transform that string into something that just looks like

  s = "jane.doe@mailserver.com"

  using introduced string methods, slicing, and variable assignment.

The english.py Library

• To facilitate working with English words, we can take advantage of the pre-written english module
  • This will be highly useful in the Wordle project!
• The english module exports two resources:
  • ENGLISH_WORDS: a constant sequence which contains all the valid English words in alphabetical order and lowercase format
  • is_english_word(): a predicate function which takes a string as input and returns True or False depending on if that string is a valid English word

Problem 3: Look Ma, No Vowels!

• Write a function which, when called, prints out all the words in the English language which do not contain vowels.
• Your function should return the length of the longest word in the English language which doesn’t contain a vowel
• Note that ENGLISH_WORDS is a sequence! So you can loop directly over it to get each word one at a time

Igpay Atinlay

• Suppose we wanted to write a script that converted English to Pig Latin
• Rules of Pig Latin:
  • If the word begins with a consonant, move everything up to the first vowel to the end and append on “ay” at the end fleet ⟶ eetflay
  • If the word starts with a vowel, just append “way” to the end orange ⟶ orangeway
  • If the word has no vowels, do nothing
• Bonus: What English words, when “Pig-Latin-ified” are still valid English words?

A Solution

from english import ENGLISH_WORDS, is_english_word

def find_first_vowel(word):
    """ 
    Finds the first vowel index in a string

    Algorithm:
        Loop through all letters
        Check if that letter is in aeiou
        If it is, immediately return the index
    """
    for i in range(len(word)):
        if word[i].lower() in "aeiou":
            return i
    return -1

def pig_latin(word):
    """
    Converts a word to its Pig Latin form

    Algorithm:
        Check the first letter to see if vowel
            Task 1 if is not vowel
                Figure out where first vowel is
                Slice and rearrange
            Task 2
                Concatenate on a way
    """
    first_vowel = find_first_vowel(word)
    if first_vowel == 0:
        # Easy tack on way
        word += "way"
    elif first_vowel > 0:
        # Find first vowel and rearrange
        first_part = word[:first_vowel]
        second_part = word[first_vowel:]
        word = second_part + first_part + "ay"
    return word




if __name__ == '__main__':
    for word in ENGLISH_WORDS:
        platin = pig_latin(word)
        if is_english_word(platin) and word != platin:
            print(word, platin))